but in precedence order && > || . Checked the same in dennis ricthie.

On Tue, Jul 26, 2011 at 2:53 PM, rajeev bharshetty <rajeevr...@gmail.com>wrote:

> Replace || by && and then j and k will get evaluated.
> The thing is that i think  when the compiler sees a || operator ,if the
> first operand is true than it wont check for the second.Thus j and k are not
> getting evaluated.
>
> On Tue, Jul 26, 2011 at 2:46 PM, Ankur Khurana 
> <ankur.kkhur...@gmail.com>wrote:
>
>> #include<iostream>
>>
>> #include<string.h>
>> using namespace std;
>> #define N(e) "e"#e
>>
>> int main()
>> {
>> int i=1,j=2,k=3;
>>     int m = i++ || j++ && k++;
>> cout<<i<<" "<<j<<" "<<k<<" "<<m;
>> }
>>
>> output :-2 2 3 1
>>
>> http://www.ideone.com/0sKBr
>>
>> can anybody explain ? why are ++j and ++k are not evaluating even though
>> && operator should be evaluated first in order of evaluation.
>>
>> Regards,
>> Ankur
>>
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>
>
>
> --
> Regards
> Rajeev N B <http://www.opensourcemania.co.cc>
>
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-- 
Ankur Khurana
Computer Science
Netaji Subhas Institute Of Technology
Delhi.

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