Sorry for the above mistake....its not O(n)

On Tue, Jul 26, 2011 at 5:29 PM, Piyush Sinha <ecstasy.piy...@gmail.com>wrote:

> Use stack
>
>
> On Tue, Jul 26, 2011 at 5:22 PM, Shikhar <shikharko...@gmail.com> wrote:
>
>> Given an array of integers, for each element of the array, print the
>> first number on the right side of the element which is smaller than
>> it. print -1 is there is no such element.
>>
>> eg: 3,4,2,18,19,1,10
>>
>> Ans: 2,2,1,10,10,-1,-1
>> O(n^2) solution is trivial.
>>
>> One solution could be:
>> Insert the elements of the array in a binary search tree. The moment a
>> node in the binary tree gets a left child, it is the element we are
>> looking for. All the nodes in the right subtree of a node which has
>> just received a left child can be assigned the value of the parents'
>> left child as the first smaller element to the right.
>> Thus, this solution is O(nlogn).
>>
>> Does this solution work for all possible cases of input?
>>
>> Is an O(n) solution possible?
>>
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>
>
> --
> *Piyush Sinha*
> *IIIT, Allahabad*
> *+91-7483122727*
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> NEVER"
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>
>


-- 
*Piyush Sinha*
*IIIT, Allahabad*
*+91-7483122727*
* <https://www.facebook.com/profile.php?id=100000655377926> "NEVER SAY
NEVER"
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