the link ll not occupy any m/y here...so its output ll be 14(int -4
bytes,ptr-2 bytes);;if i'm wrong jst crct it...
On 7/26/11, Prem Krishna Chettri <hprem...@gmail.com> wrote:
> Its Cos that is pointer and all pointers is 4 bytes address..
>
> On Tue, Jul 26, 2011 at 7:11 PM, Puneet Gautam
> <puneet.nsi...@gmail.com>wrote:
>
>> @everyone:
>> I have this mind strangling doubt..!!!
>>
>> Why is "char *s[5]" of 20 bytes...?
>>
>> yes the output is 28...
>>
>> On 7/26/11, Don <dondod...@gmail.com> wrote:
>> > A reasonable guess would be 28 bytes. But the size of a structure is
>> > implementation dependent, and therefore, some other result could be
>> > correct as well.
>> > Don
>> >
>> > On Jul 26, 7:40 am, Puneet Gautam <puneet.nsi...@gmail.com> wrote:
>> >> #include<stdio.h>
>> >> #include<stddef.h>
>> >> struct node{
>> >> int a;
>> >> char *b[5];
>> >> struct node *link;
>> >> };
>> >> main()
>> >> {
>> >> int a;
>> >> a=sizeof(struct node);
>> >> printf("%d",a);
>> >> getchar();
>> >> return 0;
>> >> }
>> >>
>> >> Whats the output..?
>> >
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//BE COOL// kavi
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