Look we wish to allocate memory for an array of 3 integer pointers.
so when we do dynamic allocation we always store the result in a pointer to
the required data type.
for example if you wish to dynamically allocate int arr[3[]
u will write :
int *p=malloc(3*sizeof(int));
So now when you do it for an array of integer pointers the result of malloc
should point to the first element of the dynamically allocated array. The
elements of the array are pointers hence the memory allocated will be saved
in a pointer that will correspond to the pointer to the first element. Since
the elements are pointers so the result of malloc will be saved to a pointer
to a pointer.
My sample program which i compiled in Dev C++ is as follows :
#include<stdio.h>
#include<conio.h>
main()
{
int a,b,c;
int **p;
p=malloc(3*sizeof(int *));
a=b=c=1;
p[0]=&a;
p[1]=&b;
p[2]=&c;
printf("%d %d %d",*p[0],*p[1],*p[2]);
getch();
}
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