@aditya..the answer may vary, because c is machine dependent
language..in few machines int is of 2 bytes and char is of 1 byte..u
can't say..it varies with diff machines
On 7/26/11, aditya kumar <aditya.kumar130...@gmail.com> wrote:
> char *s[5] is a array of pointers of type char . but the thing is size of
> pointers is 4byte irrespective of its type . coz address is always an
> unsigned int which is of 4byte.
> On Tue, Jul 26, 2011 at 7:11 PM, Puneet Gautam
> <puneet.nsi...@gmail.com>wrote:
>
>> @everyone:
>> I have this mind strangling doubt..!!!
>>
>> Why is "char *s[5]" of 20 bytes...?
>>
>> yes the output is 28...
>>
>> On 7/26/11, Don <dondod...@gmail.com> wrote:
>> > A reasonable guess would be 28 bytes. But the size of a structure is
>> > implementation dependent, and therefore, some other result could be
>> > correct as well.
>> > Don
>> >
>> > On Jul 26, 7:40 am, Puneet Gautam <puneet.nsi...@gmail.com> wrote:
>> >> #include<stdio.h>
>> >> #include<stddef.h>
>> >> struct node{
>> >> int a;
>> >> char *b[5];
>> >> struct node *link;
>> >> };
>> >> main()
>> >> {
>> >> int a;
>> >> a=sizeof(struct node);
>> >> printf("%d",a);
>> >> getchar();
>> >> return 0;
>> >> }
>> >>
>> >> Whats the output..?
>> >
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