@Prem: Each program is provided with a pool of address, which consist
of heap, stack etc.
My question is that if I write an address 0xff which is
not provided to that program then
what will be the output?
On 7/28/11, Prem Krishna Chettri <hprem...@gmail.com> wrote:
> First of all this is a good Question as this is use regularly in Device
> Driver kind of Development Mode and hence there is no question of Not
> Possible.
>
> So how to Do it is Question. which is as follows :-
>
> Point your pointer to mem add that U want and Now this Mem Add is HEX guys
> (Not 4 or 5 or any base 10 val) , so put it as 0x(whatever U want).
>
> Do whatever U want to do on that address using that pointer now.
>
> The Code above is correct but the implementation is wrong so...
>
>
> #include<stdio.h>
> int main()
> {
> int *p = (int *)0xff;
> // *p = 4; /** Dude can U put hex val here .. Oh its already assigned
> to 0xff.. **/ Now print it cout<<p<<endl;
> return 0;
> }
>
> Regards
> Prem
>
> On Thu, Jul 28, 2011 at 10:44 AM, Tyler Durden <abhishek.khattr...@gmail.com
>> wrote:
>
>> @Ankita: So when is 4000 memory address is allotted?? I mean what use does
>> int *p = 4000 serve here??
>>
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