as Number of possible sets are nCk i think complexity of the best solution
will be O(k*nCk) (as in siddarths solution)
siddharth's solution will fail in case k > 64
a simple recursive program is possible i think in same complexity.

On Thu, Jul 28, 2011 at 6:40 PM, Tushar Bindal <tushicom...@gmail.com>wrote:

> though the code given by siddharth seems to be a bit tough to understand
> due to one long statement, it gives a good idea to run the main loop fron
> 2^k -1  to (2^k - 1)*(2^(n-k)) since these rae the only numbers having k
> digits set
>
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-- 
Sunny Aggrawal
B-Tech IV year,CSI
Indian Institute Of Technology,Roorkee

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