no ,
n[0] is *(n+0)
so actually n is being dereferenced here .Check the basci diff
p is a pointer , but n is a pointer to a pointer.
On Fri, Jul 29, 2011 at 11:34 PM, Arshad Alam <alam3...@gmail.com> wrote:
> wow great... but why it is so yaar?
> ptr=n and ptr=n[0] is same na?
>
>
> On Fri, Jul 29, 2011 at 11:27 PM, rajeev bharshetty
> <rajeevr...@gmail.com>wrote:
>
>> #include<stdio.h>
>>
>> void main()
>> {
>> int n[3][3]= {
>> 2,4,3,
>> 6,8,5,
>> 3,5,1
>> };
>> int i,*ptr;
>> ptr= n;
>> for(i=0;i<=8;i++)
>> printf("\n%d",*(ptr+i));
>>
>> }
>>
>> In gcc 4.3.2 no error ,it is just showing a warning as
>>
>> ms50.c: In function ‘main’:
>> ms50.c:11:8: warning: assignment from incompatible pointer type
>>
>> change the statement as ptr = n[0] warning vanishes
>>
>> On Fri, Jul 29, 2011 at 11:17 PM, Arshad Alam <alam3...@gmail.com> wrote:
>>
>>> what's the problem with line number 12?
>>>
>>> 1 #include<stdio.h>
>>> 2 #include<conio.h>
>>> 3 void main()
>>> 4 {
>>> 5 clrscr();
>>> 6 int n[3][3]= {
>>> 7 2,4,3,
>>> 8 6,8,5,
>>> 9 3,5,1
>>> 10 };
>>> 11 int i,*ptr;
>>> 12 ptr=n;
>>> 13 for(i=0;i<=8;i++)
>>> 14 printf("\n%d",*(ptr+i));
>>> 15 getch();
>>> }
>>>
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>>
>>
>>
>> --
>> Regards
>> Rajeev N B <http://www.opensourcemania.co.cc>
>>
>> "*Winners Don't do Different things , they do things Differently"*
>>
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>
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--
Ankur Khurana
Computer Science
Netaji Subhas Institute Of Technology
Delhi.
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