the warning comes is as
warning: passing argument 1 of ‘foo’ from incompatible pointer type
foo expects a constant char** but it is not the case...hence warning is
displayed.......
remove the const keyword.....you'll see no warning !!
--
Amol Sharma
Third Year Student
Computer Science and Engineering
MNNIT Allahabad
On Sat, Jul 30, 2011 at 5:30 PM, kartik sachan <kartik.sac...@gmail.com>wrote:
>
> #include <stdio.h>
> void foo(const char **p) { }
> int main(int argc, char **argv)
> {
> foo(argv);
> return 0;
> }
>
> why the above code giving me warning can body explain me??
>
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