any specific reason fr maintaining a BST...can we simply have 2 more
arrays...one dat keeps order and the oder that keeps count
correspondingly...
is a BST more efficient than an array??

On Sun, Jul 31, 2011 at 12:43 AM, nivedita arora <
vivaciousnived...@gmail.com> wrote:

> take a BST whose node has an element of frequency .and another array
> which will store order of elements.
> for each array element search BST if node already exists increase the
> freq count ..other wise  add that element in the order array we took
> and insert new node in BST.
>
> now , scan the order array find its corresponding element in BST and
> its frequency, print it that many times.
>
> let me know if there is any bttr method
> thx!
>
> On Jul 30, 11:58 pm, sukhmeet singh <sukhmeet2...@gmail.com> wrote:
> > maintain a count array of all elements..
> > now traverse the array again and the count array .. and build the new
> array
> >
> > On Sun, Jul 31, 2011 at 12:24 AM, aditi garg <aditi.garg.6...@gmail.com
> >wrote:
> >
> >
> >
> >
> >
> >
> >
> > > Q1) Given an array with some repeating numbers. Like 12,6,5,12,6
> > > output: 12,12,6,6,5
> >
> > > 12 shud come before 6 since it is earlier in list. Please provide a
> > > gud algo fr dis
> >
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-- 
Aditi Garg
Undergraduate Student
Electronics & Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
New Delhi

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