int mypow(int x,int m)
{
if(m==0)
return 1;
if(m==1)
return x;
return mypow(x,ceil((float)m/2))*mypow(x,m/2);
}
On Sat, Jul 30, 2011 at 1:02 PM, arvind kumar <arvindk...@gmail.com> wrote:
> Find the least time complexity algorithm(most efficient algo) to find
> x^m(x to the power of m)..Facebok intern interview question!
>
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