Whats the logic behind
**a^=*b;*
**b^=*a;*
**a^=*b;*
??
On Sun, Jul 31, 2011 at 7:19 PM, rajeev bharshetty <rajeevr...@gmail.com>wrote:
> *#include<stdio.h>*
> *int main()*
> *{*
> *int i=10;*
> *int j=20;*
> *int *a,*b;*
> *a =&i;*
> *b=&j;*
> *printf("before""%d%d\n",*a,*b);*
> **a^=*b;*
> **b^=*a;*
> **a^=*b;*
> *printf("after""%d%d",*a,*b);*
> *return 0;*
> *}*
> *
> *
> *This swaps pointers .... *
>
> On Sun, Jul 31, 2011 at 7:15 PM, Nikhil Gupta
> <nikhilgupta2...@gmail.com>wrote:
>
>> How to swap two pointers without using a temporary pointer ?
>>
>> --
>> Nikhil Gupta
>> Senior Co-ordinator, Publicity
>> CSI, NSIT Students' Branch
>> NSIT, New Delhi, India
>>
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>
>
>
> --
> Regards
> Rajeev N B <http://www.opensourcemania.co.cc>
>
> "*Winners Don't do Different things , they do things Differently"*
>
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--
Nikhil Gupta
Senior Co-ordinator, Publicity
CSI, NSIT Students' Branch
NSIT, New Delhi, India
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