#include<iostream>
#include<stdio.h>
using namespace std;
class Base
{
public:
Base()
{
fun(); //note: fun() is virtual
}
virtual void fun()
{
cout<<"\nBase Function";
}
};
class Derived: public Base
{
public:
Derived(){}
virtual void fun()
{
cout<<"\nDerived Function";
}
};
int main()
{
Base* pBase = new Derived();
delete pBase;
getchar();
return 0;
}
Output:
*Base Function*
See following excerpt from C++
standard<http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2005/n1905.pdf>for
explanation.
*When a virtual function is called directly or indirectly from a constructor
(including from the mem-initializer for a data member) or from a destructor,
and the object to which the call applies is the object under construction or
destruction, the function called is the one defined in the constructor or
destructor’s own class or in one of its bases, but not a function overriding
it in a class derived from the constructor or destructor’s class, or
overriding it in one of the other base classes of the most derived object.*
Because of this difference in behavior, it is recommended that object’s
virtual function is not invoked while it is being constructed or destroyed.
See this
<https://www.securecoding.cert.org/confluence/display/cplusplus/OOP30-CPP.+Do+not+invoke+virtual+functions+from+constructors+or+destructors>for
more details.
..............CAN ANYONE GIVE A SIMPLE EXPLANANTION?? given explanation is
quite confusing....
--
Regards,
$iva
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