thanks it really helpd me a lot.........
On Tue, Aug 2, 2011 at 3:16 AM, Dharmendra Modi <
dharmendra.modi...@gmail.com> wrote:
> The first part initialization of for loop (i<=5 && i>=-1) is just an
> initialization and nothing else. It is of no use in this case.
>
> The second part condition holds the condition which is in this case +
> +i specifying to run loop till i is non zero. You are using prefix
> operator hence it will first increment i and then test.
> If you have used i++ the loop wont even have executed single time.
>
> The condition ++i becomes zero when there is round of short and you
> get zero at that time the loop terminates.
>
> The format specifier for unsigned int is used hence positive values
> are printed.
> If the format specifier for %d is used then the results would be more
> informative.
>
> Hope that helps.
>
> On Aug 1, 11:51 pm, jagrati verma <jagrativermamn...@gmail.com> wrote:
> > #include<stdio.h>
> > main()
> > {
> > short int i=0;
> > for(i<=5 && i>=-1;++i;i>0)
> > printf("%u\n",i);
> > printf("\n");
> > return 0;}
> >
> > o/p is 1.....
> > 4294967295 hw???????????????????????????
>
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