there absolutely nothing wrong in your interpretation.
here is a link that might help : http://www.unix.org/whitepapers/64bit.html


On 4 August 2011 11:18, Shashank Jain <shashan...@gmail.com> wrote:

> see dipankar, i hv 64 bit OS nd processor bt i dont know abt the compiler.
> nd yeah size of int is 4 bytes. so tell me where im interpreting wrong?
>
> Shashank Jain
> 3rd year, Computer Engg.
> Delhi College of Engineering
>
>
>
> On Thu, Aug 4, 2011 at 11:16 AM, Dipankar Patro <dip10c...@gmail.com>wrote:
>
>> This has been a hot topic of discussion for a long time. But I found there
>> are two things to look into it:
>>
>> 1. a 64 bit OS is one, which has 64 bit address handling capacity. and a
>> 64bit processor is one which can perform operations on 64 bit data. A
>> general concept that actually gets overlooked by many. Even I was confused
>> with differences of 64 bit OS and Processors a while back.
>>
>> 2. if a compiler by it's own doesn't support 64 bit, it might be the case
>> that even if you run on a 64 bit OS, size of int will be 4 bytes (32 bit).
>>
>> I think the best way to check out is to make a code on 64 bit compiler. If
>> somebody has tried it please share the results.
>>
>> On 4 August 2011 10:38, Tushar Bindal <tushicom...@gmail.com> wrote:
>>
>>> never assume that he compiler is same as the OS you run. it may be that
>>> you are running a 32-bit compiler
>>>
>>> I think pointers have size 4bytes on 8 byte compiler also - not sure.
>>> someone please correct me.
>>>
>>>
>>> On Thu, Aug 4, 2011 at 10:26 AM, Shashank Jain <shashan...@gmail.com>wrote:
>>>
>>>> the size of a pointer is showing 4 bytes in my 64-bit OS, which should
>>>> have been 8 bytes. Correct me where i am wrong?
>>>>
>>>> Shashank Jain
>>>> 3rd year, Computer Engg.
>>>> Delhi College of Engineering
>>>>
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