I think this will do.
http://en.wikipedia.org/wiki/Midpoint_circle_algorithm

On Fri, Aug 5, 2011 at 7:08 PM, rShetty <rajeevr...@gmail.com> wrote:

> Write a routine to draw a circle (x ** 2 + y ** 2 = r ** 2) without
> making use of any floating point
> computations at all.
>
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