http://trickofmind.com/?p=1080
i think this will help, we need to find Carmichael number or somthing
related to ETF for the input number.

On Sat, Aug 6, 2011 at 12:24 PM, Nikhil Gupta <nikhilgupta2...@gmail.com>wrote:

> @sumit, these numbers containing all ones are not in binary representation.
> They are in decimal system.
>
>
> On Sat, Aug 6, 2011 at 9:51 AM, sahil gujral <gujralsa...@gmail.com>wrote:
>
>> yes u r wrong..
>> 111111111 is nt divisible by 23
>>
>>
>> On Sat, Aug 6, 2011 at 9:15 AM, sumit <sumitispar...@gmail.com> wrote:
>>
>>> This looks quite simple.
>>> Every number ending in 3 follows a pattern.eg-
>>> 3 - 111
>>> 13 - 111111
>>> 23 - 111111111 etc
>>> we can find the reauired no. by :
>>> suppose input no. is 33
>>> In every case leave the no at 1's place(least significant) i.e. 3, In
>>> 33 you will be left with 3(after removal of 3 at first place).
>>> Now ,3 *(rest of nos +1 ) is your answer (in case of 33 it is 3*(3+1)
>>> = 12 i.e  111111111111).
>>> for 103 it is 3*(10+1) = 33 1's.
>>>
>>> Correct if I am wrong.
>>>
>>>
>>> On Aug 5, 4:33 pm, Manee <mani.ma...@gmail.com> wrote:
>>> > ADOBE asks the very basic C/C++ questions
>>> >
>>> > one of their toughest however was :
>>> >
>>> > every number ending in 3 has a multiple of the form "111...111"
>>> >
>>> > e.g 3 has 111
>>> >  13 has 111111
>>> > so on..
>>> >
>>> > find the algo for finding the number for an input number ending in 3.
>>> >
>>> > On Aug 5, 2:33 pm, Agyat <jalsa.n.sa...@gmail.com> wrote:
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> > > hey, guys adobe is visiting our campus. So those who know questions
>>> > > that adobe asked in written or interview, please post here as it will
>>> > > be of great help (as adobe has visited some colleges already).
>>> > > Thank you in advance.
>>>
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>
>
>
> --
> Nikhil Gupta
> Senior Co-ordinator, Publicity
> CSI, NSIT Students' Branch
> NSIT, New Delhi, India
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