sorry two cases only

On Sat, Aug 6, 2011 at 6:21 AM, UTKARSH SRIVASTAV
<usrivastav...@gmail.com>wrote:

> pseudo code
>
>        three cases are possible
>   1.node has left and right child
>      then inorder succesor will be leftmost child of right child
> 2.   node has left child and no right child or no left and right chid
>      if node is left child of it's parent then inorder succesor is it's
> parent only
>      if node is right child of it's parent then keep on moving upwards
> until you find a parent which is left child of it's parent
>  then it will be the inorder succesor....if you reach node then no inorder
> succesor
>
> --
> *UTKARSH SRIVASTAV
> CSE-3
> B-Tech 3rd Year
> @MNNIT ALLAHABAD*
>
>


-- 
*UTKARSH SRIVASTAV
CSE-3
B-Tech 3rd Year
@MNNIT ALLAHABAD*

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