padding should depend on m/c size according to my logic....
On Sat, Aug 6, 2011 at 9:32 PM, sukran dhawan <sukrandha...@gmail.com>wrote:
> it all depends on word size of the computer.since int by default is equal
> to word size and double usually occupies 8 bytes all of these start from a
> new memory boundary.so if only part of it filled rest of them will be
> holes.tat is the whole reason why structures cannot be compared for equality
> and its a syntax error
>
> On Sat, Aug 6, 2011 at 9:28 PM, Aditya Virmani
> <virmanisadi...@gmail.com>wrote:
>
>> i guess it depends on ur system configuration...for 32 bit
>> machines...respective sizes allocated would be 4,4,8 :giving 16
>> & on 64 bit machines it wud be 8,8,8: giving 24. Correct me if i am wrong.
>>
>>
>> On Sat, Aug 6, 2011 at 9:24 PM, SANDEEP CHUGH <sandeep.aa...@gmail.com>wrote:
>>
>>> @ sukran , nitish :
>>> guys, i dnt knw about the output from these online compliers..
>>>
>>>
>>> On Sat, Aug 6, 2011 at 9:20 PM, SANDEEP CHUGH
>>> <sandeep.aa...@gmail.com>wrote:
>>>
>>>>
>>>> @payel : according to u,,starting address cannot be 4.. ok.
>>>> but wat if i hav used the following structure before that structure
>>>>
>>>> struct demo1
>>>> {
>>>> char a;
>>>> int b;
>>>> char c;
>>>>
>>>> }
>>>>
>>>>
>>>> On Sat, Aug 6, 2011 at 9:06 PM, Nitish Garg
>>>> <nitishgarg1...@gmail.com>wrote:
>>>>
>>>>> Why does Ideone https://ideone.com/1Uwxx gives 16?
>>>>>
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--
Saurabh Singh
B.Tech (Computer Science)
MNNIT ALLAHABAD
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