@Utkarsh: And what is the complexity of making a bst? So will the
complexity of your suggestion be more or less than O(n)?

Dave

On Aug 7, 8:07 pm, UTKARSH SRIVASTAV <usrivastav...@gmail.com> wrote:
> i think searching for largest or smallest number may be O(n) so make a bst
> and do it's inorder traversal last three elements will have max product
>
> On Sun, Aug 7, 2011 at 2:05 PM, victory tunn <loserinvict...@gmail.com>wrote:
>
>
>
>
>
> > @Punnet : why to find smallest three. SMALLEST here means negative
> > numbers//
> > lets say smallest1 is smaller than smallest2 and larget1>larget2>larget3
> > I think we just need to find smallest 2( because -ve * -ve = pos);
>
> > then result = max( smallest1*smallet2*largest1 , larget1,larget2,larget3)
>
> > Please correct me If I am wrong
> > Thanks,
>
> > On Sun, Aug 7, 2011 at 9:31 PM, sukran dhawan <sukrandha...@gmail.com>wrote:
>
> >> good approach
>
> >> On Sun, Aug 7, 2011 at 6:41 PM, Puneet Ginoria 
> >> <punnu.gino...@gmail.com>wrote:
>
> >>> find the first three largest nos. and 3 smallest number(negatives).. then
> >>> easily you can fig. out the solution..
>
> >>> O(6n) solution i guess which is O(n)....
>
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> *UTKARSH SRIVASTAV
> CSE-3
> B-Tech 3rd Year
> @MNNIT ALLAHABAD*

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