@debrata : bt remember its a recursive function...once the leaf node gets
deleted thn it will move bak to the node and thn to the left of it
fr eg
a
/ \
b c
/ \ / \
d e f g
frst g will be deleted...then f thn it wil delete c and so on...i think the
ans shud be 1...correct me if i am wrong...
On Mon, Aug 8, 2011 at 10:49 PM, Debabrata Das <
debabrata.barunhal...@gmail.com> wrote:
> check this condition
> if( node->left == NULL && node->right == NULL )
> it is true only for leaves node
>
> On Mon, Aug 8, 2011 at 10:46 PM, rajul jain <rajuljain...@gmail.com>
> wrote:
> > I have also made same answer on first look but read 3rd option correctly
> it
> > say deletion of leaves from right to left not internal nodes.
> >
> > On Mon, Aug 8, 2011 at 10:36 PM, Debabrata Das
> > <debabrata.barunhal...@gmail.com> wrote:
> >>
> >> i think 3
> >>
> >> On Mon, Aug 8, 2011 at 10:32 PM, rajul jain <rajuljain...@gmail.com>
> >> wrote:
> >> > got it thanks
> >> >
> >> > On Mon, Aug 8, 2011 at 10:30 PM, Akash Mukherjee <akash...@gmail.com>
> >> > wrote:
> >> >>
> >> >> i think its 1 though .......
> >> >>
> >> >> On Mon, Aug 8, 2011 at 10:21 PM, rohit <rajuljain...@gmail.com>
> wrote:
> >> >>>
> >> >>> What will the following code snippet do, when is it passed the root
> of
> >> >>> a binary tree ?
> >> >>> func( Node *node){
> >> >>>
> >> >>> if(node->right != NULL)
> >> >>>
> >> >>> func( node->right);
> >> >>>
> >> >>> if(node->left != NULL)
> >> >>>
> >> >>> func( node->left);
> >> >>>
> >> >>> if( node->left == NULL && node->right == NULL )
> >> >>>
> >> >>> delete(node);
> >> >>>
> >> >>> }
> >> >>>
> >> >>> Pick choice
> >> >>> Delete the tree from bottom to top
> >> >>>
> >> >>> Delete the tree from top to bottom
> >> >>>
> >> >>> Delete the leaf nodes from right to left
> >> >>>
> >> >>> Delete the leaf nodes from left to right
> >> >>>
> >> >>> I think it is 3
> >> >>>
> >> >>> --
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--
Aditi Garg
Undergraduate Student
Electronics & Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
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