@prakash
it will be 2*12C6*2*6C3*2*6C2

2 each for either side, left and right

On Tue, Aug 9, 2011 at 3:00 PM, Prakash D <cegprak...@gmail.com> wrote:

> 12C6* 6c3 * 6C2
>
> On Tue, Aug 9, 2011 at 2:10 PM, programming love <
> love.for.programm...@gmail.com> wrote:
>
>> members
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-- 
**Regards
SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD

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