1. Square each element of the array and then sort it---------------O(nlogn)
2. for(i=0;i<(size-3);i++)
{
j=i+1; k=size-1;
while(j<k)
{
if(a[[i] + a[j] == a[k])
printf("\n%d %d %d",sqrt(a[i]),sqrt(a[j]),sqrt(a[k]));
else if(a[i] + a[j] < a[k])
j++;
else
k--;
}
}------------------------------------------------------------------------O(n^2)
Time O(n^2)
--
You received this message because you are subscribed to the Google Groups
"Algorithm Geeks" group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.
