@sandeep: so the statement becomes if(ch=0) since printf returns integer
0...whats does this mean now actually?0 is ascii for NULL and so ch is
assinged to null? I am slightly confused..
On Tue, Aug 9, 2011 at 7:04 PM, SANDEEP CHUGH <sandeep.aa...@gmail.com>wrote:
> @all sorry i give wrong explanation by mistake..:P :P
>
> printf("") returns no if characters.. in this case returns 0 . which is
> assigned to ch
>
> so in ch 0 is stored and 0 is the ascii value of null character
> when we using ch in --- if (ch) --> it will reduce to if(0) -- as 0 is the
> ascii value of null character
>
> so the output "it doesn't matter"
>
>
> On Tue, Aug 9, 2011 at 10:28 PM, Dipankar Patro <dip10c...@gmail.com>wrote:
>
>> o/p:
>> It doesn't matter
>>
>> Reason:
>> printf() returns the number of characters printed to screen.
>> since printf("") will return 0, hence the *else* is selected.
>>
>>
>> On 9 August 2011 22:25, siddharth srivastava <akssps...@gmail.com> wrote:
>>
>>>
>>>
>>> On 9 August 2011 22:20, tech rascal <techrascal...@gmail.com> wrote:
>>>
>>>> #include<stdio.h>
>>>> int main()
>>>> {
>>>> char ch;
>>>> if((ch=printf("")))
>>>> printf("it matters");
>>>> else
>>>> printf("it doesn't matter");
>>>> return 0;
>>>> }
>>>>
>>>>
>>> It doesn't matter
>>>
>>>
>>>
>>>>
>>>> what will b the output??
>>>>
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>>>
>>>
>>>
>>> --
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>>> Siddharth Srivastava
>>>
>>>
>>>
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>>
>>
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