@aditya . (int*)0 is pointing to Null value , so (int*)0+1 will be 0x4
which is the size of int as implemented in compiler . so basically
your code is returning sizeof(int) which will always return 4 which is
equivalent to 32 bits .
I couldn't check this program on a 64 bit machine ( p.s. mine support
64 bit but the OS is 32 bit )
but I guess it will return 32 on 64 bit machine as well
I may be wrong, so If you have run this code and found 64 than let me know.
On Thu, Aug 11, 2011 at 5:59 PM, aditya kumar
<aditya.kumar130...@gmail.com> wrote:
> printf("%d",((int)((int *)0 + 1))*8);
> o/p :: 32/64
> On Thu, Aug 11, 2011 at 5:14 PM, sukran dhawan <sukrandha...@gmail.com>
> wrote:
>>
>> thanks
>>
>> On Thu, Aug 11, 2011 at 5:02 PM, Aditya Virmani <virmanisadi...@gmail.com>
>> wrote:
>>>
>>> u can never find tht thru ur prgm...sizeof int is compiler dependant
>>> whether its 32/64 bit...
>>>
>>> On Thu, Aug 11, 2011 at 4:35 PM, sukran dhawan <sukrandha...@gmail.com>
>>> wrote:
>>>>
>>>> how to determine whether the machine is a 32 bit or 64 bit using a c
>>>> program?
>>>> is it by sizeof(int) * 4?
>>>>
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--
Rohit Jangid
Under Graduate Student,
Deptt. of Computer Engineering
NSIT, Delhi University, India
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