if the hash function evaluates to 3 or 4 , collision occurs and by linear probing they are put into 5(nearest free entry). Also 5 and 6 are empty.
But if the hash value points to 7,8,9,10 or 1 , they will be put into 2(nearest free entry). On Thu, Aug 11, 2011 at 10:53 PM, Mani Bharathi <manibharat...@gmail.com>wrote: > how do u say that they will lead to 2? > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To view this discussion on the web visit > https://groups.google.com/d/msg/algogeeks/-/d9eo_cbjCvwJ. > > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
