if it were if(a,b,y,x) then output wud hav been EXAM
On Fri, Aug 12, 2011 at 4:14 AM, Prakash D <cegprak...@gmail.com> wrote:
> @anuj kumar: try this
>
> #include<stdio.h>
> #include<string.h>
> int main()
> {
> int a=10,b=20;
> char x=1,y=0;
> printf("%d\n",a,b,x,y);
> printf("%d\n",(a,b,x,y));
>
> if(a,b,x,y)
> {
> printf("EXAM");
> }
> getchar();
> }
>
> this will print 10 and 0
> because if the outer bracket is not there, only the first element is
> considered it ignores the rest. if there is a bracket it just pushes into
> the stack left to right and the last element is considered..
>
> within if, there is no outer brackets but it tries to convert to bool and
> statement will execute like "if((bool)(a,b,x,y))"
> so the if condition fails
>
> correct me if i'm wrong
>
> On Thu, Aug 11, 2011 at 5:18 PM, sukran dhawan <sukrandha...@gmail.com>wrote:
>
>> the output should be blank. because comma is a operator in c which
>> associates from left to right. so each of a ,b,x,y is evaluated and y is the
>> last one to be evaluated and its value(0) is returned as the value of the
>> expression.so the if condition returns false.
>> i dont understand how u got that output !
>>
>>
>> On Thu, Aug 11, 2011 at 4:29 PM, Prem Krishna Chettri <hprem...@gmail.com
>> > wrote:
>>
>>> Yep,
>>>
>>> Ideally, if() statement evaluates the last push stack value from the
>>> stack and apparently here the last value evaluates to be 0 resulting the
>>> failure of the if condition.
>>>
>>> Please verify the compilation. :)
>>>
>>> Prem
>>>
>>>
>>> On Thu, Aug 11, 2011 at 4:21 PM, hary rathor <harry.rat...@gmail.com>wrote:
>>>
>>>> print nothing , your output is wrong
>>>>
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