1.scan the array and find the maximum digits of integer. lets say m..
2.Again scan the array and pad the intergers whose digits are less that m (<
m) with zero's .. copy the new integers in a new array
3.sort the new array in desc order and carry the same even for original
array.
4. Now the original array contains the required output.
ex: original aarray 23,8,19,9,1

max digits : 2 (for 23 as well as 19)
step 2: new array 23,80,19,90,10
step3. sort .. 90,80,23,19,10 .. and corresponding original is .. 98231910.

original array contains the original output..



On Sat, Aug 13, 2011 at 7:15 AM, chengjie qi <starboy...@gmail.com> wrote:

> int compare(int a, int b) {
> string s = Integer.tostring(a);
> string y = Integer.tostring(b);
> if (s +y < y+s)
>    return -1;
> else
>    return 1;
> }
>
>
>  use this to write quick sort , you can get the answer.
>
> On Fri, Aug 12, 2011 at 8:34 PM, Yasir Imteyaz <yasir....@gmail.com>wrote:
>
>> An array of integers is given and you have to find the largest possible
>> integer by concatenating all elements:
>>
>> example:
>> array:  87  36  52
>> answer:  875236
>>
>> array: 87 9 52
>> answer: 98752
>>
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>
>
>
> --
> stay hungry stay foolish
> Chengjie Qi
>
>
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-- 
Thx,
--Gopi

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