typo in above code..find t(n+1)

On Sun, Aug 14, 2011 at 12:37 AM, Kamakshii Aggarwal
<kamakshi...@gmail.com>wrote:

> if steps are between banks then try dis.
> if n=3 steps
> then find t(n+2)
> and use the fibonacci formula t(n)=t(n-1)+t(n-2)
> t(1)=1;
> t(2)=2;
> now this will work ...
>
>
> On Sun, Aug 14, 2011 at 12:34 AM, Kamakshii Aggarwal <
> kamakshi...@gmail.com> wrote:
>
>> i am sorry.i misinterpret the question...i dint c that the steps are
>> between   banks..
>>
>>
>> On Sun, Aug 14, 2011 at 12:26 AM, ankit tyagi <ankittya...@gmail.com>wrote:
>>
>>> seems fine..
>>>
>>>
>>> On Sun, Aug 14, 2011 at 12:13 AM, Mohit Goel 
>>> <mohitgoel291...@gmail.com>wrote:
>>>
>>>> there are 5 possibilities ..5th one is    _12_..other as specified by
>>>> ankit...
>>>>
>>>>
>>>> t(1) =2  (it can directly jump to anathor bank)
>>>> t(2) =3 ( _2_,_1_,_12_)
>>>>
>>>> t(3) =5...
>>>> thats how fibonnaci goes on ....plz correct if wrong...
>>>>
>>>>
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>>
>>
>>
>> --
>> Regards,
>> Kamakshi
>> kamakshi...@gmail.com
>>
>
>
>
> --
> Regards,
> Kamakshi
> kamakshi...@gmail.com
>



-- 
Regards,
Kamakshi
kamakshi...@gmail.com

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