Well, this can have undefined behavior. Technically you should append
- First allocate memory for a string
- Then append the terminating char
In this case, the memory location after the last character is set to
zero, but then you do not have control over it. It may not be zero
when you run it the next time. So it might not terminate.
On Sun, Aug 14, 2011 at 10:24 AM, Arshad Alam <alam3...@gmail.com> wrote:
> program is running smooth but I have one confusion at line number 8.
> why it is while(s[i]!=0) instead of while(s[i]!='\0')
>
>
>
> 1. #include<stdio.h>
> 2. #include<conio.h>
> 3. void main()
> 4. {
> 5. clrscr();
> 6. char s[]="No two viruses";
> 7. int i=0;
> 8. while(s[i]!=0)
> 9. {
> 10. printf("\n%c %c",s[i],*(s+i));
> 11. printf ( "\n%c %c",i[s],*(i+s));
> 12. i++;
> 13. }
> 14. getch();
> 15. }
>
>
>
>
> Thanks & Regards
> Arshad Nadeem Alam
>
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Gaurav Menghani
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