8 times 12 is 96
96 + 1
is
97
take sqrt(97)
9.8488578017961047217462114149176

now 9.8488578017961047217462114149176 minus 1
EQUALS
8.8488578017961047217462114149176
Half IT
And Take The Ceiling of it = 5





On Sun, Aug 14, 2011 at 8:05 PM, Anika Jain <anika.jai...@gmail.com> wrote:

> plz tell me that for this triangle.. if 12 is given then what to do?
>
> On Sun, Aug 14, 2011 at 7:49 PM, muruga vel <murugavidya1...@gmail.com>wrote:
>
>> I  was asked to find out the no of rows given n . i.e. how we say 4 rows
>> for 10 ???
>>  On 14 Aug 2011 10:54, "sagar pareek" <sagarpar...@gmail.com> wrote:
>> > here is sudo code
>> >
>> > take two variables
>> >
>> > int max=1;
>> > int count=1;
>> > int i,total_no_of_rows;
>> >
>> > while(total_no_of_rows--)
>> > {
>> > for(i=0;i<count;i++)
>> > {
>> > printf("%d ",max-i);
>> > }
>> > printf("\n");
>> > count++;
>> > max+=count;
>> > }
>> >
>> > On Sun, Aug 14, 2011 at 10:25 AM, Rahul <raikra...@gmail.com> wrote:
>> >
>> >> @Beginner
>> >> If You Know How to implement a series whose difference in terms form An
>> >> Arithmetic Progression
>> >>
>> >> Then Is quite easy
>> >> to print the (n)TH Line
>> >> Add n to the highest number seen so far and then subtract the 1 for n
>> >> times (p = n-- , check for p )
>> >>
>> >> @Everyone Else
>> >> Can anyone one think of a more elegant method , to find #rows
>> >>
>> >>
>> >> Rahul
>> >>
>> >>
>> >> On Sun, Aug 14, 2011 at 10:09 AM, Ankur Khurana <
>> ankur.kkhur...@gmail.com>wrote:
>> >>
>> >>> to print from 10 to 7 in the row number 4. here prev will be 6.
>> >>>
>> >>>
>> >>> On Sun, Aug 14, 2011 at 10:05 AM, AASHISH SUMAN <
>> >>> aashish.barn...@gmail.com> wrote:
>> >>>
>> >>>> @ankur
>> >>>>
>> >>>> what is the need of
>> >>>> prev=((i-)*i)/2;
>> >>>>
>> >>>>
>> >>>>
>> >>>>
>> >>>> On Sun, Aug 14, 2011 at 9:51 AM, Ankur Khurana <
>> ankur.kkhur...@gmail.com
>> >>>> > wrote:
>> >>>>
>> >>>>> see , we can see that
>> >>>>> first lline have 1 number, second have 2 and third have 3 .....and
>> so
>> >>>>> on. we can observe that first number of every row is sum of first k
>> narutal
>> >>>>> number, where k is the row number. so for k=4, n=((4+1)*4)/2=10;
>> >>>>>
>> >>>>> so run a for loop,
>> >>>>>
>> >>>>>
>> >>>>> for(int i=1;i<num_rows;i++)
>> >>>>> {
>> >>>>> prev=((i-)*i)/2;
>> >>>>> k=((i+1)*i)/2;
>> >>>>> for(int j=k;i;k>prev;j--)
>> >>>>> {
>> >>>>> cout<<prev<<" ";
>> >>>>> }
>> >>>>> cout<<endl;
>> >>>>> }
>> >>>>>
>> >>>>>
>> >>>>> On Sun, Aug 14, 2011 at 9:43 AM, Dave <dave_and_da...@juno.com>
>> wrote:
>> >>>>>
>> >>>>>> @Beginner: The largest number n in row r satisfies n = (r^2 + r) /
>> 2.
>> >>>>>> So using the Quadratic Formula gives
>> >>>>>>
>> >>>>>> r = ( sqrt( 8*n + 1 ) - 1 ) / 2.
>> >>>>>>
>> >>>>>> For the row number r for any n (not necessarily the largest one in
>> a
>> >>>>>> row),
>> >>>>>>
>> >>>>>> r = ceil( sqrt( 8*n + 1 ) - 1 ) / 2 )
>> >>>>>>
>> >>>>>> where ceil( x ) is the smallest integer not exceeding x.
>> >>>>>>
>> >>>>>> Dave
>> >>>>>>
>> >>>>>> On Aug 13, 10:22 pm, Beginner <murugavidya1...@gmail.com> wrote:
>> >>>>>> > How to print this triangle?
>> >>>>>> > 1
>> >>>>>> > 3 2
>> >>>>>> > 6 5 4
>> >>>>>> > 10 9 8 7
>> >>>>>> > and how to find the number of rows if n is given?
>> >>>>>> > For ex if n=10 how to find num of rows=4??
>> >>>>>> > Is it Log 10 to the base of 2!!!!!!
>> >>>>>>
>> >>>>>> --
>> >>>>>> You received this message because you are subscribed to the Google
>> >>>>>> Groups "Algorithm Geeks" group.
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>> >>>>>> To unsubscribe from this group, send email to
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>> >>>>>>
>> >>>>>>
>> >>>>>
>> >>>>>
>> >>>>> --
>> >>>>> Ankur Khurana
>> >>>>> Computer Science
>> >>>>> Netaji Subhas Institute Of Technology
>> >>>>> Delhi.
>> >>>>>
>> >>>>> --
>> >>>>> You received this message because you are subscribed to the Google
>> >>>>> Groups "Algorithm Geeks" group.
>> >>>>> To post to this group, send email to algogeeks@googlegroups.com.
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>> >>>>>
>> >>>>
>> >>>>
>> >>>>
>> >>>> --
>> >>>> *WITH BEST REGARDS :
>> >>>>
>> >>>> AASHISH SUMAN
>> >>>> MCA FINAL YEAR
>> >>>> *
>> >>>> *NIT DURGAPUR*
>> >>>> *+91-9547969906*
>> >>>>
>> >>>> --
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>> >>>>
>> >>>
>> >>>
>> >>>
>> >>> --
>> >>> Ankur Khurana
>> >>> Computer Science
>> >>> Netaji Subhas Institute Of Technology
>> >>> Delhi.
>> >>>
>> >>> --
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>> >>>
>> >>
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>> >
>> >
>> >
>> > --
>> > **Regards
>> > SAGAR PAREEK
>> > COMPUTER SCIENCE AND ENGINEERING
>> > NIT ALLAHABAD
>> >
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