8 times 12 is 96 96 + 1 is 97 take sqrt(97) 9.8488578017961047217462114149176
now 9.8488578017961047217462114149176 minus 1 EQUALS 8.8488578017961047217462114149176 Half IT And Take The Ceiling of it = 5 On Sun, Aug 14, 2011 at 8:05 PM, Anika Jain <anika.jai...@gmail.com> wrote: > plz tell me that for this triangle.. if 12 is given then what to do? > > On Sun, Aug 14, 2011 at 7:49 PM, muruga vel <murugavidya1...@gmail.com>wrote: > >> I was asked to find out the no of rows given n . i.e. how we say 4 rows >> for 10 ??? >> On 14 Aug 2011 10:54, "sagar pareek" <sagarpar...@gmail.com> wrote: >> > here is sudo code >> > >> > take two variables >> > >> > int max=1; >> > int count=1; >> > int i,total_no_of_rows; >> > >> > while(total_no_of_rows--) >> > { >> > for(i=0;i<count;i++) >> > { >> > printf("%d ",max-i); >> > } >> > printf("\n"); >> > count++; >> > max+=count; >> > } >> > >> > On Sun, Aug 14, 2011 at 10:25 AM, Rahul <raikra...@gmail.com> wrote: >> > >> >> @Beginner >> >> If You Know How to implement a series whose difference in terms form An >> >> Arithmetic Progression >> >> >> >> Then Is quite easy >> >> to print the (n)TH Line >> >> Add n to the highest number seen so far and then subtract the 1 for n >> >> times (p = n-- , check for p ) >> >> >> >> @Everyone Else >> >> Can anyone one think of a more elegant method , to find #rows >> >> >> >> >> >> Rahul >> >> >> >> >> >> On Sun, Aug 14, 2011 at 10:09 AM, Ankur Khurana < >> ankur.kkhur...@gmail.com>wrote: >> >> >> >>> to print from 10 to 7 in the row number 4. here prev will be 6. >> >>> >> >>> >> >>> On Sun, Aug 14, 2011 at 10:05 AM, AASHISH SUMAN < >> >>> aashish.barn...@gmail.com> wrote: >> >>> >> >>>> @ankur >> >>>> >> >>>> what is the need of >> >>>> prev=((i-)*i)/2; >> >>>> >> >>>> >> >>>> >> >>>> >> >>>> On Sun, Aug 14, 2011 at 9:51 AM, Ankur Khurana < >> ankur.kkhur...@gmail.com >> >>>> > wrote: >> >>>> >> >>>>> see , we can see that >> >>>>> first lline have 1 number, second have 2 and third have 3 .....and >> so >> >>>>> on. we can observe that first number of every row is sum of first k >> narutal >> >>>>> number, where k is the row number. so for k=4, n=((4+1)*4)/2=10; >> >>>>> >> >>>>> so run a for loop, >> >>>>> >> >>>>> >> >>>>> for(int i=1;i<num_rows;i++) >> >>>>> { >> >>>>> prev=((i-)*i)/2; >> >>>>> k=((i+1)*i)/2; >> >>>>> for(int j=k;i;k>prev;j--) >> >>>>> { >> >>>>> cout<<prev<<" "; >> >>>>> } >> >>>>> cout<<endl; >> >>>>> } >> >>>>> >> >>>>> >> >>>>> On Sun, Aug 14, 2011 at 9:43 AM, Dave <dave_and_da...@juno.com> >> wrote: >> >>>>> >> >>>>>> @Beginner: The largest number n in row r satisfies n = (r^2 + r) / >> 2. >> >>>>>> So using the Quadratic Formula gives >> >>>>>> >> >>>>>> r = ( sqrt( 8*n + 1 ) - 1 ) / 2. >> >>>>>> >> >>>>>> For the row number r for any n (not necessarily the largest one in >> a >> >>>>>> row), >> >>>>>> >> >>>>>> r = ceil( sqrt( 8*n + 1 ) - 1 ) / 2 ) >> >>>>>> >> >>>>>> where ceil( x ) is the smallest integer not exceeding x. >> >>>>>> >> >>>>>> Dave >> >>>>>> >> >>>>>> On Aug 13, 10:22 pm, Beginner <murugavidya1...@gmail.com> wrote: >> >>>>>> > How to print this triangle? >> >>>>>> > 1 >> >>>>>> > 3 2 >> >>>>>> > 6 5 4 >> >>>>>> > 10 9 8 7 >> >>>>>> > and how to find the number of rows if n is given? >> >>>>>> > For ex if n=10 how to find num of rows=4?? >> >>>>>> > Is it Log 10 to the base of 2!!!!!! >> >>>>>> >> >>>>>> -- >> >>>>>> You received this message because you are subscribed to the Google >> >>>>>> Groups "Algorithm Geeks" group. >> >>>>>> To post to this group, send email to algogeeks@googlegroups.com. >> >>>>>> To unsubscribe from this group, send email to >> >>>>>> algogeeks+unsubscr...@googlegroups.com. >> >>>>>> For more options, visit this group at >> >>>>>> http://groups.google.com/group/algogeeks?hl=en. >> >>>>>> >> >>>>>> >> >>>>> >> >>>>> >> >>>>> -- >> >>>>> Ankur Khurana >> >>>>> Computer Science >> >>>>> Netaji Subhas Institute Of Technology >> >>>>> Delhi. >> >>>>> >> >>>>> -- >> >>>>> You received this message because you are subscribed to the Google >> >>>>> Groups "Algorithm Geeks" group. >> >>>>> To post to this group, send email to algogeeks@googlegroups.com. >> >>>>> To unsubscribe from this group, send email to >> >>>>> algogeeks+unsubscr...@googlegroups.com. >> >>>>> For more options, visit this group at >> >>>>> http://groups.google.com/group/algogeeks?hl=en. >> >>>>> >> >>>> >> >>>> >> >>>> >> >>>> -- >> >>>> *WITH BEST REGARDS : >> >>>> >> >>>> AASHISH SUMAN >> >>>> MCA FINAL YEAR >> >>>> * >> >>>> *NIT DURGAPUR* >> >>>> *+91-9547969906* >> >>>> >> >>>> -- >> >>>> You received this message because you are subscribed to the Google >> Groups >> >>>> "Algorithm Geeks" group. >> >>>> To post to this group, send email to algogeeks@googlegroups.com. >> >>>> To unsubscribe from this group, send email to >> >>>> algogeeks+unsubscr...@googlegroups.com. >> >>>> For more options, visit this group at >> >>>> http://groups.google.com/group/algogeeks?hl=en. >> >>>> >> >>> >> >>> >> >>> >> >>> -- >> >>> Ankur Khurana >> >>> Computer Science >> >>> Netaji Subhas Institute Of Technology >> >>> Delhi. >> >>> >> >>> -- >> >>> You received this message because you are subscribed to the Google >> Groups >> >>> "Algorithm Geeks" group. >> >>> To post to this group, send email to algogeeks@googlegroups.com. >> >>> To unsubscribe from this group, send email to >> >>> algogeeks+unsubscr...@googlegroups.com. >> >>> For more options, visit this group at >> >>> http://groups.google.com/group/algogeeks?hl=en. >> >>> >> >> >> >> -- >> >> You received this message because you are subscribed to the Google >> Groups >> >> "Algorithm Geeks" group. >> >> To post to this group, send email to algogeeks@googlegroups.com. >> >> To unsubscribe from this group, send email to >> >> algogeeks+unsubscr...@googlegroups.com. >> >> For more options, visit this group at >> >> http://groups.google.com/group/algogeeks?hl=en. >> >> >> > >> > >> > >> > -- >> > **Regards >> > SAGAR PAREEK >> > COMPUTER SCIENCE AND ENGINEERING >> > NIT ALLAHABAD >> > >> > -- >> > You received this message because you are subscribed to the Google >> Groups "Algorithm Geeks" group. >> > To post to this group, send email to algogeeks@googlegroups.com. >> > To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> > For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.