The internal representation of array is this: suppose that the address starts from decimal number 10 and integer occupies 2 bytes
10- 0002 ( num 2 in hex) 12- 0003 ( num 3 in hex) 14- 0004 ( num 4 in hex) Now p points to address 10 and is type char. (Even after type casts) p+1 will increment address by 1 byte (since it's char). p will now point to 11 (int *) will say that when de-referenced 2 bytes should be extracted. So the 2 bytes extracted are 11, 12. Numbers in these bytes are 02 and 00 10- 00*02* ( num 2 in hex) 12- *00*03 ( num 3 in hex) 14- 0004 ( num 4 in hex) now (char *) says extract 1 byte for me. The extracted byte is 00. Hence 0 is printed *Correct me if i am wrong.* -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
