int lol=2; // total lol's encountered upto now
lol++;
On Mon, Aug 15, 2011 at 12:41 AM, aditi garg <aditi.garg.6...@gmail.com>wrote:
> lol
>
>
> On Mon, Aug 15, 2011 at 12:40 AM, aditya kumar <
> aditya.kumar130...@gmail.com> wrote:
>
>> @aditi : sry i dint realise that n > log n .:P
>>
>> On Mon, Aug 15, 2011 at 12:38 AM, aditi garg
>> <aditi.garg.6...@gmail.com>wrote:
>>
>>> @aditya : dis is obviously correct bt here complexity will be O(n) bt we
>>> are asked to gv O(log n) solution
>>>
>>> On Mon, Aug 15, 2011 at 12:37 AM, aditya kumar <
>>> aditya.kumar130...@gmail.com> wrote:
>>>
>>>> for(j=0;j<n;j++)
>>>> {
>>>> if(a[j]==j)
>>>> return j;
>>>> else
>>>> continue ;
>>>> }
>>>>
>>>> this shud also be correct right ??
>>>>
>>>> On Mon, Aug 15, 2011 at 12:31 AM, Akash Mukherjee
>>>> <akash...@gmail.com>wrote:
>>>>
>>>>> just my 2 cents ---- in d binary search, replacing key with mid, ie
>>>>> if(a[mid] > mid)
>>>>> check lower half
>>>>> else upper half
>>>>>
>>>>> should work??
>>>>>
>>>>>
>>>>> On Mon, Aug 15, 2011 at 12:26 AM, aditi garg <
>>>>> aditi.garg.6...@gmail.com> wrote:
>>>>>
>>>>>> Given an ordered array A[1…n] with numbers in strictly increasing
>>>>>> order. Find a ‘j’ such that A [j]=j or -1 if no such number exist in
>>>>>> o (log n).
>>>>>>
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>>>
>>>
>>>
>>> --
>>> Aditi Garg
>>> Undergraduate Student
>>> Electronics & Communication Divison
>>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>>> Sector 3, Dwarka
>>> New Delhi
>>>
>>>
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>>
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>
>
>
> --
> Aditi Garg
> Undergraduate Student
> Electronics & Communication Divison
> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> Sector 3, Dwarka
> New Delhi
>
>
> --
> You received this message because you are subscribed to the Google Groups
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>
--
**Regards
SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD
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