I think.i hv seen this code somewhere ..geeksforgeek may be

On 8/16/11, Ankuj Gupta <ankuj2...@gmail.com> wrote:
> we take the difference with the maximum element found so far. So we
> need to keep track of 2 things:
> 1) Minimum difference found so far (min_diff).
> 2) Maximum number visited so far (max_element).
> min_diff=abs(a[0]-a[1]);
> max_elem=a[0]
> for(i=1;i<arr_size;i++)
> if(abs(max_elem-a[i])<min_diff)
>       min_diff = abs(max_elem-a[i]);
> if(a[i]>max_elem)
>       max_elem=a[i];
>
> Ankuj
> On Aug 16, 7:26 pm, Shuaib Khan <aries.shu...@gmail.com> wrote:
>> Dave, I agree. :)
>>
>>
>>
>>
>>
>>
>>
>>
>>
>> On Tue, Aug 16, 2011 at 6:33 PM, Dave <dave_and_da...@juno.com> wrote:
>> > @Shuaib: We are talking about an array of numbers, arent't we? It is
>> > natural to assume that the numbers fall into one of the defined data
>> > types.
>>
>> > Dave
>>
>> > On Aug 16, 4:23 am, Shuaib <aries.shu...@gmail.com> wrote:
>> > > Yes it will work in this specific case. What I meant was that Radix
>> > > sort
>> > isn't always applicable in general to achieve linear time sorting. Its
>> > complexity isn't exactly O(N) rather O(d*N) where d is the number of
>> > bytes
>> > each of our item consumes. So if the elements in array aren't from a
>> > finite
>> > range, that would be an issue.
>>
>> > > Correct me if I am wrong.
>>
>> > > --
>> > > Shuaibhttp://twitter.com/ShuaibKhanhttp://www.bytehood.com/
>>
>> > > On 16-Aug-2011, at 11:05 AM, Dave <dave_and_da...@juno.com> wrote:
>>
>> > > > @Shuaib: It will work in all cases. If you don't think so, give a
>> > > > counterexample.
>>
>> > > > Dave
>>
>> > > > On Aug 16, 12:50 am, Shuaib <aries.shu...@gmail.com> wrote:
>> > > >> That will work but not in all cases as radix sort isn't a
>> > > >> generalized
>> > sorting algorithm, is it? :)
>>
>> > > >> --
>> > > >> Shuaibhttp://twitter.com/ShuaibKhanhttp://www.bytehood.com/
>>
>> > > >> On 16-Aug-2011, at 10:10 AM, Dave <dave_and_da...@juno.com> wrote:
>>
>> > > >>> @Shuaib: You could sort the numbers in O(n) with a radix sort, and
>> > > >>> then finding the min is easy. Mind you, the radix sort might be
>> > slower
>> > > >>> than an O(n log n) sort, but still it satisfies the O(n)
>> > > >>> constraint.
>>
>> > > >>> Dave
>>
>> > > >>> On Aug 15, 8:41 pm, Shuaib <aries.shu...@gmail.com> wrote:
>> > > >>>> That won't work. And I don't think an O(n) solution is possible.
>>
>> > > >>>> --
>> > > >>>> Shuaibhttp://twitter.com/ShuaibKhanhttp://www.bytehood.com/
>>
>> > > >>>> On 16-Aug-2011, at 6:25 AM, sukran dhawan
>> > > >>>> <sukrandha...@gmail.com>
>> > wrote:
>>
>> > > >>>>> find the minimum of two numbers in a loop o(n) and subtract the
>> > > >>>>> two
>>
>> > > >>>>> On Tue, Aug 16, 2011 at 6:13 AM, Brijesh Upadhyay <
>> > brijeshupadhyay...@gmail.com> wrote:
>> > > >>>>> Algorithm to find the two numbers whose difference is minimum
>> > > >>>>> among
>> > the set of numbers. For example the sequence is 5, 13, 7, 0, 10, 20, 1,
>> > 15,
>> > 4, 19 The algorithm should return min diff = 20-19 = 1. Constraint -
>> > Time
>> > Complexity O(N)
>>
>> > > >>>>> --
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>> --
>> Shuaibhttp://www.bytehood.comhttp://twitter.com/ShuaibKhan
>
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-- 
Somnath Singh

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