i cudnt understand how is it done here by using xor by chen.. aftergetting F
it wud be the xor of of odd occuring elements, fine, then he wrote if(xor)A1
==0 how is this logic used??

On Wed, Aug 17, 2011 at 8:17 AM, saurabh singh <saurab...@gmail.com> wrote:

> +1 to dave.....xor is the way to go.....
>
>
> On Tue, Aug 16, 2011 at 7:06 PM, Dave <dave_and_da...@juno.com> wrote:
>
>> @Raghavan: But aren't maps implemented as binary search trees? That
>> would make insertion and searching O(log n), and the overall operation
>> O(n log n).
>>
>> Dave
>>
>> On Aug 16, 4:08 am, Raghavan <its...@gmail.com> wrote:
>> > @sukran:
>> > If you were asking for the map based solution
>> >
>> > space and time complexity would be o(n).
>> >
>> > On Tue, Aug 16, 2011 at 2:34 PM, sukran dhawan <sukrandha...@gmail.com
>> >wrote:
>> >
>> >
>> >
>> >
>> >
>> > > what is the complexity in which it has been done ?
>> >
>> > > On Tue, Aug 16, 2011 at 1:41 PM, MAC <macatad...@gmail.com> wrote:
>> >
>> > >> Given an array of integers. Each number in the array repeats ODD
>> number of
>> > >> times, but only 1 number repeated for EVEN number of times. Find that
>> > >> number.
>> >
>> > >> --
>> > >> thanks
>> > >> --mac
>> >
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>> > Raghavan KL
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>
>
> --
> Saurabh Singh
> B.Tech (Computer Science)
> MNNIT ALLAHABAD
>
>
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