@Sanjay: In the longest common subsequence we have the continuous elements
but here he has placed no restriction on that..

On Wed, Aug 17, 2011 at 9:06 PM, Raghavan <its...@gmail.com> wrote:

> @sanjay:
>
> Thats cool
>
>
> On Wed, Aug 17, 2011 at 9:02 PM, Sanjay Rajpal <srn...@gmail.com> wrote:
>
>> I think it is similar to longest increasing subsequence problem .
>> Try the following link :
>> http://en.wikipedia.org/wiki/Longest_increasing_subsequence
>>
>> Sanjay Kumar
>> B.Tech Final Year
>> Department of Computer Engineering
>> National Institute of Technology Kurukshetra
>> Kurukshetra - 136119
>> Haryana, India
>>
>>
>>
>>
>> On Wed, Aug 17, 2011 at 8:26 AM, Raghavan <its...@gmail.com> wrote:
>>
>>>
>>>
>>> Given an unsorted array (A), find the max size of set in which the
>>> numbers should be in the incremental order.
>>>
>>>
>>> For example: A = [7,* 2, 3*, 1, *5, 8, 9*, 6]
>>>
>>>
>>> The possible set with max numbers (in increment order) is {2, 3, 5, 8, 9}
>>> and the result is: 5.
>>>
>>> Note:
>>> 1. The final set can begin at any index.
>>> 2. It can skip any numbers which comes in between the array (here we
>>> skipped {7, 1, 6}).
>>>
>>> how to do this?
>>>
>>> --
>>> Thanks and Regards,
>>> Raghavan KL
>>>
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>
>
>
> --
> Thanks and Regards,
> Raghavan KL
>
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-- 
Romil

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