We know that n+m+s+carry < 10. So n<7. We also know that either n+n+n or o+o+o > 9 because there must be a carry to make those two columns add to a different value. We can start eliminating values for n. If n is 1, o would have to be 7 to make the second row work out. But then u and e would both be 3. If n is 3, o must be 1, so u would also be 3. If n is 4, o must be 1 and u must be 3, which makes n+m+s > 9. If n=5, then e would be 5, so n can't be 5. If n is larger than 5, there is no combination which makes n+m+s<10. That leaves n=2. It follows that e=6, o=4, and u=3. m and s are interchangeable: 1 and 5. And j is 9.
2442+1442+5442=9326 Don On Aug 17, 1:23 pm, priya ramesh <love.for.programm...@gmail.com> wrote: > noon > + moon > + soon > = june > > find the values of the alphabets to satisfy this equation -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
