@Dave

How did you get the complexity as O(n log k)

On Aug 18, 8:14 am, Dave <dave_and_da...@juno.com> wrote:
> @Aditi: Form a max-heap of the first 100 numbers. Then as you read the
> remaining numbers, if a number is less than the root of the max-heap,
> replace the root with it and restore the heap condition. When you
> reach the end of the million numbers, the heap will contain the
> smallest 100 numbers.
>
> If there are n numbers and you want the smallest k, this algorithm is
> O(n log k).
>
> Dave
>
> On Aug 17, 10:05 pm, aditi garg <aditi.garg.6...@gmail.com> wrote:
>
>
>
>
>
>
>
> > How to find the set of smallest 100 numbers out of 1 million numbers...

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