but why only o/p-00 00 AC 40 and not AC 40 00 00 or 00 AC 40 00 or 40 AC 00
00etc , plz explain in detail how p[0] pts to 00 and p[1] pts to 00 and p[2]
pts AC or 1010 1100 and p[3] pts to 40 or 0100 0000 ONLY in this
way..............Vijay Khandar...........
On Sat, Aug 20, 2011 at 12:31 PM, Dipankar Patro <dip10c...@gmail.com>wrote:
> float is 4 bytes.
> so a=3.75 will be stored in 4 bytes in memory.
>
> the moment you have a pointer referring to the same memory location but
> type cast to (char *), the pointer will refer to character i.e. 1 byte.
> ^^ this explains the p[0] , p[1], p[2], p[3] <- 4 bytes of the 3.75
>
> now finally the o/p
> 00 00 AC 40
> ^^ it is in little endian format. i.e the data bytes are stored in memory
> is reverse format.
>
> On 20 August 2011 11:21, Vijay Khandar <vijaykhand...@gmail.com> wrote:
>
>> If the binary equivalent of 5.375 in normalised form is - 0100 0000
>> 1010 0000 1100 0000 0000 0000
>>
>> what is the o/p of following code-
>> main()
>> {
>> float a=5.375;
>> char *p;
>> int i;
>> p=(char *)&a;
>> for(i=0;i<=3;i++)
>> printf("%02X",(unsigned char)p[i]);
>> }
>>
>> O/P= 00 00 AC 40
>> Plz, Plz anyone explain me in detail, how this o/p is coming?
>> Vijay..........
>>
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