Is const a compiler level construct ?
#include <stdio.h>
int main() {
const int i = 0;
int * p ;
p = (int *) & i;
*p = 2;
printf("(i,p): %x %x \n",&i,p);
printf("(i,p): %d %d \n",i,*p);
}
I ran this program and got this output.Can somebody explain ?
(i,p): bfc3de6c bfc3de6c
(i,p): 0 2
On Sat, Aug 20, 2011 at 10:08 AM, sukran dhawan <sukrandha...@gmail.com>wrote:
> may be it places the variable in read only memory
>
>
> On Thu, Aug 18, 2011 at 2:38 AM, bihari <kumarvive...@gmail.com> wrote:
>
>> How to prevent the compiler to alter the value of i in statement:
>> const int i=2;
>> Just give the idea about the implementation of const int i=somevalue;
>>
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regards,
chinna.
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