@tushar:

thanks

On Sun, Aug 21, 2011 at 12:27 PM, Tushar Bindal <tushicom...@gmail.com>wrote:

> if the cyclist would have left on time, then in those 20 minutes, he would
> have covered 4miles at a speed of 12miles/h
> so he would have been 1 mile before station whereas train would have been 5
> miles before as it is on its normal time, so no change in its position.
> then, when the cyclist covers that 1 mile, the train covers 5 miles so that
> both of them meet at the station.
> thus, speed of the train = 5*speed of cyclist = 60 miles/hour
>
>
> On Sun, Aug 21, 2011 at 12:19 PM, prasanth n <nprasnt...@gmail.com> wrote:
>
>> @gupta:
>>
>> can you explain your answer?
>>
>>
>> On Sun, Aug 21, 2011 at 1:50 AM, D!leep Gupta 
>> <dileep.smil...@gmail.com>wrote:
>>
>>> 60mph
>>>
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>>
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>
>
>
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> Tushar Bindal
> Computer Engineering
> Delhi College of Engineering
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