#include<iostream>
using namespace std;
class base
{
public:
int bval;
base(){bval=0;}
};
class deri:public base
{
public:
int dval;
deri(){dval=1;}
};
void SomeFunc(base *arr,int size)
{
for(int i=0; i<size; i++,arr++)
{ cout<<arr->bval<<endl;
cout<<&(arr->bval)<<endl;
}
cout<<endl;
}
int main()
{
base BaseArr[5];
SomeFunc(BaseArr,5);
deri DeriArr[5];
SomeFunc(DeriArr,5);
system("pause");
return 0;
}
see the output u will understant
On Sun, Aug 21, 2011 at 12:44 PM, Puneet Chawla
<puneetchawla...@gmail.com>wrote:
> Wil u please explain in context of o/p.means how 1 whn SomeFunc(DeriArr,5);
> stmt is executed how 0 and 1 will come..???
>
>
> On Sun, Aug 21, 2011 at 12:40 PM, Naman Mahor <naman.ma...@gmail.com>wrote:
>
>> because the pointer of base class will move by 2 bytes every time but the
>> size of derived class is 4 byte.
>>
>>
>> On Sun, Aug 21, 2011 at 12:31 PM, Puneet Chawla <
>> puneetchawla...@gmail.com> wrote:
>>
>>> class base
>>> {
>>> public:
>>> int bval;
>>> base(){bval=0;}
>>> };
>>> class deri:public base
>>> {
>>> public:
>>> int dval;
>>> deri(){dval=1;}
>>> };
>>> void SomeFunc(base *arr,int size)
>>> {
>>> for(int i=0; i<size; i++,arr++)
>>> cout<<arr->bval;
>>> cout<<endl;
>>> }
>>> int main()
>>> {
>>> base BaseArr[5];
>>> SomeFunc(BaseArr,5);
>>> deri DeriArr[5];
>>> SomeFunc(DeriArr,5);
>>> system("pause");
>>> return 0;
>>> }
>>>
>>> 00000
>>> 01010
>>> Will somebody tell me why it's showing this..??
>>>
>>> --
>>> With regards
>>> ............
>>> Puneet
>>>
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>>
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>
>
>
> --
> With regards
> ............
> Puneet
>
> --
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