FUNC2(8)
==> 8==0? 1: 8 * FUNC1(8-1)
==> 8==0? 1: 8*( 8-1* 8-1-1)
==> 8 * (8-8-2)
==> -16
but why 16??
On Sat, Aug 20, 2011 at 7:02 PM, SuDhir mIsHra <sudhir08.mis...@gmail.com>wrote:
> #include<stdio.h>
> #define FUNC1(i) (i*(i-1))
> #define FUNC2(i) (i==0?1:i*FUNC1(i-1))
> main()
> {
> int i=8;
>
>
> printf("\n%d",FUNC2(i));
> }
>
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