It all depends on the definition of no *extra space.*For me the question was
ambigous....

On Mon, Aug 22, 2011 at 12:27 AM, Amol Sharma <amolsharm...@gmail.com>wrote:

> i'll go with the first option...since no extra space is allowed....
>
> this ques was asked by amazon in written in our college.....don't know the
> correct answer...it all depends on what
> "Most efficient data structure" is............i.e what option they do
> frequently min or push or pop....
>
> btw....what's the right answer??
> --
>
>
> Amol Sharma
> Third Year Student
> Computer Science and Engineering
> MNNIT Allahabad
>  <http://gplus.to/amolsharma99> 
> <http://twitter.com/amolsharma99><http://in.linkedin.com/pub/amol-sharma/21/79b/507><http://youtube.com/amolsharma99>
>
>
>
>
>
> On Sun, Aug 21, 2011 at 11:07 PM, dilip makwana 
> <dilipmakwa...@gmail.com>wrote:
>
>> If we can have additional O(n) space than all operations wil take O(1)
>> ..additional MinStack implementation..
>>
>> But if we are  not allowed O(n) space then at  the cost of GetMinimum to
>> become O(1) we have to sacrifice for push and pop to be O(n)..{this is not
>> mentioned in option}
>>
>> So most efficient will be O(1) time for each
>>
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-- 
Saurabh Singh
B.Tech (Computer Science)
MNNIT ALLAHABAD

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