using interval tree/segment tree will solve this in straightforward
fashion

On Aug 22, 12:41 pm, Jagannath Prasad Das <jpdasi...@gmail.com> wrote:
> for the stick prob is the stick length required?
>
> On Mon, Aug 22, 2011 at 12:48 PM, Jagannath Prasad Das
> <jpdasi...@gmail.com>wrote:
>
>
>
>
>
>
>
> > i think find max and min of all time-stamps respectively
>
> > On Mon, Aug 22, 2011 at 12:44 PM, saurabh agrawal 
> > <saurabh...@gmail.com>wrote:
>
> >> How did u solved :
>
> >> 3) There is a list containing the checkin and checkout time of every
> >> person in a party . The checkin time is in ascending order while the
> >> checkout is random .
>
> >> Eg:
>
> >>                        Check_in                Check_out
>
> >> Person 1             8.00                          9.00
>
> >> Person 2             8.15                          8.30
>
> >> Person 3             8.30                          9.20
>
> >> On Mon, Aug 22, 2011 at 9:14 AM, Decipher <ankurseth...@gmail.com> wrote:
>
> >>> Hi,
>
> >>> This is my Adobe interview experience for freshers :
>
> >>>  *Written Test:*
>
> >>> Engineering               – 45 Minutes - Data Structures, Algorithms,
> >>> Operating Systems****
>
> >>> C/C++                      – 45 Minutes - C/C++ Fundamentals & Coding***
> >>> *
>
> >>> Aptitude                    – 45 Minutes – Quantitative & Analytical
>
> >>> * *
>
> >>> *On clearing the Test, 3 Technical Interviews + HR discussion on the
> >>> same day.*
>
> >>> *
> >>> *
>
> >>> *Interview 1: *
>
> >>> 1) Insert an element in a linked list at the end , given the *start *
> >>> pointer.
>
> >>> 2) Write a function to Swap pointers .
>
> >>> 3) There is a list containing the checkin and checkout time of every
> >>> person in a party . The checkin time is in ascending order while the
> >>> checkout is random .
>
> >>> Eg:
>
> >>>                        Check_in                Check_out
>
> >>> Person 1             8.00                          9.00
>
> >>> Person 2             8.15                          8.30
>
> >>> Person 3             8.30                          9.20
>
> >>> and so on ...
> >>> Now , give an optimized solution to find at what time the maximum number
> >>> of people will be in the party . My solution - O(nlogn) time and O(n) 
> >>> space
> >>> . He gave another O(nlogn) time and O(n) space solution .
>
> >>> and some other questions that I can't recal ......
>
> >>> *Interview 2:*
> >>> 1) Base class contains 2 functions and Derived class (with Private
> >>> Inheritance from Base) also contains 2 functions (same name as those in 
> >>> Base
> >>> cass), then he asked me the effect by changing the Inheritance type and
> >>>  making different functions virtual like - virtual func in Base then in
> >>> Derived and then both .
>
> >>> 2) Same question appended- A derived class *A* derived from Derived and
> >>> Base , now
>
> >>> A a = new A;
> >>> Base *b =  a;
> >>> Derived *d = a;
>
> >>> b = d;
>
> >>> and b = (Base *) d;
>
> >>> then which functions can I call ?
>
> >>> 3) Convert a tree into its mirror without using extra memory - O(1) space
> >>> .
>
> >>> 4) If an array is rotated a number of unknown times , then how to find an
> >>> element in O(log n)
>
> >>> 5) There are 3 sticks placed at right angles to each other and a sphere
> >>> is placed between the sticks . Now another sphere is placed in the gap
> >>> between the sticks and Larger sphere . Find the radius of smaller sphere 
> >>> in
> >>> terms of radius of larger sphere .
>
> >>> *This is as far I can remember so please don't ask any questions
> >>> regarding it .*
>
> >>>  --
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