is it not possible to traverse tree in order and store in array. then figure
out the element and print the previous element?

On Fri, Aug 26, 2011 at 2:04 PM, Vikram Singh <singhvikram...@gmail.com>wrote:

> i figured out algo to find the inorder predecessor of a bst without
> using parent pointer... just wanna confirm if its missing any case....
>
> if the left child(subtree) of node exist, then predecessor ll be the
> max value in the left subtree.
>
> else predecessor ll be one of the ancestor.... in this case, starting
> from the given node, we hv to find a closest ancestrous node which is
> right child of its parent... the parent ll be the predecessor...
>
> and i made the parent implementation without changing the structure of
> the node... using while loop...
>
> let me know if i m missing ant case...
>
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