@dave i was saying if user enter a+b in which a>intmax .. A goes
negative(if a sligtly >intmax)  a+b =no overflow which we know
shouldnt be an answer..

On 8/28/11, Dave <dave_and_da...@juno.com> wrote:
> @Kunal: You are very kind.
>
> Dave
>
> On Aug 27, 12:58 pm, Kunal Patil <kp101...@gmail.com> wrote:
>> @Dave: Still your approach to solve the problem remains correct.
>> (subtracting a number from max possible value & then comparing this
>> difference with another number). So, no need to think that you were brain
>> dead (If you were, you would have posted a movie story here)..[?]
>> Mathematically it is wrong, not in terms of approach..[?]
>>
>> On Sat, Aug 27, 2011 at 11:02 PM, dipit grover
>> <digo.d.b...@gmail.com>wrote:
>>
>>
>>
>> > I think you just need to reverse the comparison operators in Dave's
>> > earlier
>> > post
>>
>> > On Sat, Aug 27, 2011 at 10:59 PM, Dave <dave_and_da...@juno.com> wrote:
>>
>> >> @Abishek: I was brain-dead in my earlier posting. Let me try again:
>>
>> >> If either number is zero, the sum will not overflow.
>> >> If the numbers have different signs, the sum will not overflow.
>> >> If both numbers are positive, overflow will occur if b > maxint - a.
>> >> If both numbers are negative, overflow will occur if b < -maxint - a -
>> >> 1.
>>
>> >> Dave
>>
>> >> On Aug 27, 12:18 pm, Abhishek <mailatabhishekgu...@gmail.com> wrote:
>> >> > @Dave: i didn't understand,
>> >> > suppose a=30000, b=31000 and MaxInt=32000;
>> >> > you are saying if (MaxInt-a)>=b; then overflow will occur. but here
>> >> > condition is not satisfying.
>> >> > plz explain.
>>
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>> > --
>> > Dipit Grover
>> > B.Tech in CSE
>> > IIT Roorkee
>>
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