@Navneet: I suggest that you do an in-order traversal. Assign x values
to the nodes sequentially, with y values based on the depth from the
root. Thus, in your example, d has coordinates (0,2), b: (1,1), e:
(2,2), a: (3,0), f: (4,2), c: (5,1), g: (6,2).

Dave

On Aug 28, 9:46 am, Navneet Gupta <navneetn...@gmail.com> wrote:
> Hope the question is clear. Basically you need to print a given tree
> such that spaces will depict the left/right relation at every level.
>
> output should be something like
>                     a
>                  b     c
>               d   e  f   g
>
> Levels are separated by new lines. Notice that space between nodes at
> higher levels increases with the number of levels we have. Assume a
> max of 10 levels. But the algorithm should scale.
>
> --
> Regards,
> Navneet

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