@dave well that was basically a query if it is possible to eliminate all the
operators and do something like addition operation.I am sorry if I
presentted my question in the wrong way....I am bad at explaining things.:(
Going by your previous records I am not elibigle to contradict you.....

On Mon, Aug 29, 2011 at 9:02 AM, Dave <dave_and_da...@juno.com> wrote:

> @Saurabh: Function calls and commas are operators, so that leaves out
> your clever printf solution.
>
> See
> http://en.wikipedia.org/wiki/Operators_in_C_and_C%2B%2B#Other_operators.
>
> Dave
>
> On Aug 28, 9:32 pm, saurabh singh <saurab...@gmail.com> wrote:
> > @dave even '=' is an operator.....I wonder if its possible to restrict
> *all
> > operators*.....
> >
> >
> >
> >
> >
> > On Sun, Aug 28, 2011 at 1:32 AM, Dave <dave_and_da...@juno.com> wrote:
> > > @Brijesh: Maybe you mean
> >
> > > char *p;
> > > p = (char*)a;
> > > sum = (int)&p[b]; // sum = a + b
> >
> > > but & is an operator.
> >
> > > Dave
> >
> > > On Aug 27, 2:07 pm, Brijesh <brijeshupadhyay...@gmail.com> wrote:
> > > > How to add two nos without using any operator...?
> >
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> > --
> > Saurabh Singh
> > B.Tech (Computer Science)
> > MNNIT ALLAHABAD- Hide quoted text -
> >
> > - Show quoted text -
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-- 
Saurabh Singh
B.Tech (Computer Science)
MNNIT ALLAHABAD

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