@dave:is there any other method than sorting?

On Wed, Aug 31, 2011 at 12:19 AM, Dave <dave_and_da...@juno.com> wrote:

> @Kamakshii: With O(1) extra space, it can be done with O(n)
> comparisons. Do a radix sort on the input (no comparisons), and then
> check adjacent numbers for equality.
>
> Dave
>
> On Aug 30, 1:34 pm, Kamakshii Aggarwal <kamakshi...@gmail.com> wrote:
> > develop an algorithm to find duplicates in a list of numbers without
> using a
> > binary tree..if there are n distinct numbers in the list ,how many times
> > must two numbers be compared for equality in your algorithm?what if all
> > numbers are equal?
> >
> > --
> > Regards,
> > Kamakshi
> > kamakshi...@gmail.com
>
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-- 
Regards,
Kamakshi
kamakshi...@gmail.com

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